Jawaban:
Halo, cara pengerjaan dan jawabannya ada di lampiran yaa.
Jawaban :
1. 49 √2
2. 1
3. -2-2√3
3. -2-√6
Penjelasan dengan langkah-langkah:
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Soal no. 1
[tex]\tt 7\sqrt{7} \times \sqrt{14}[/tex]
[tex]= \tt 7\sqrt{7 \times 14}[/tex]
[tex]= \tt 7\sqrt{98}[/tex]
[tex]= \tt 7\sqrt{49 \times 2}[/tex]
[tex]= \tt 7.7\sqrt{2}[/tex]
[tex]= \tt 49\sqrt{2}[/tex]
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Soal no. 2
[tex]\tt (\sqrt{3} + \sqrt{2})(\sqrt{3} - \sqrt{2})[/tex]
[tex]= \tt \sqrt{3}^2 - \sqrt{2}^2[/tex]
[tex]= \tt 3 - 2[/tex]
[tex]= \tt 1[/tex]
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Soal no. 3
[tex]\tt \dfrac{4}{1 - \sqrt{3}}[/tex]
[tex]= \tt \dfrac{4}{1 - \sqrt{3}} \times \dfrac{1 + \sqrt{3}}{1 + \sqrt{3}}[/tex]
[tex]= \tt \dfrac{4(1 + \sqrt{3})}{(1 - \sqrt{3})(1 + \sqrt{3})}[/tex]
[tex]= \tt \dfrac{4(1 + \sqrt{3})}{1^2 - \sqrt{3}^2}[/tex]
[tex]= \tt \dfrac{4(1 + \sqrt{3})}{1 - 3}[/tex]
[tex]= \tt \dfrac{\cancel{4}(1 + \sqrt{3})}{\cancel{-2}}[/tex]
[tex]= \tt - 2(1 + \sqrt{3})[/tex]
[tex]= \tt - 2 - 2\sqrt{3}[/tex]
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Soal no. 4
[tex]\tt \dfrac{\sqrt{2}}{\sqrt{2} - \sqrt{3}}[/tex]
[tex]= \tt \dfrac{\sqrt{2}}{\sqrt{2} - \sqrt{3}} \times \dfrac{\sqrt{2} + \sqrt{3}}{\sqrt{2} + \sqrt{3}}[/tex]
[tex]= \tt \dfrac{\sqrt{2}(\sqrt{2} + \sqrt{3})}{(\sqrt{2} - \sqrt{3})(\sqrt{2} + \sqrt{3})}[/tex]
[tex]= \tt \dfrac{\sqrt{2}(\sqrt{2} + \sqrt{3})}{\sqrt{2}^2 - \sqrt{3}^2}[/tex]
[tex]= \tt \dfrac{\sqrt{2}(\sqrt{2} + \sqrt{3})}{2 - 3}[/tex]
[tex]= \tt \dfrac{\sqrt{2}(\sqrt{2} + \sqrt{3})}{- 1}[/tex]
[tex]= \tt - \sqrt{2}(\sqrt{2} + \sqrt{3})[/tex]
[tex]= \tt - \sqrt{2}\sqrt{2} - \sqrt{2}\sqrt{3}[/tex]
[tex]= \tt - 2 - \sqrt{6}[/tex]
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